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  • An ideal gas is taken through the cycle <img alt="\mathrm{ A \rightarrow B \rightarrow C \rightarrow A}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%20A%20%5Crightarrow%2

An ideal gas is taken through the cycle \mathrm{ A \rightarrow B \rightarrow C \rightarrow A} as shown in the figure. If the net heat supplied to the gas in the cycle is \mathrm{5 \mathrm{~J}}, the work done by the gas in the process \mathrm{C \rightarrow A} is :
 

Option: 1

-5 \mathrm{~J}

 


Option: 2

-10 \mathrm{~J}
 


Option: 3

-15 \mathrm{~J}
 


Option: 4

-20 \mathrm{~J}


Answers (1)

best_answer

\mathrm{\Delta W_{A B}=P \Delta V =(10)(2-1)=10 \mathrm{~J} }

\mathrm{\Delta W_{B C} =0 \quad \text { (as } V=\text { constant) } }

From first law of thermodynamics

\mathrm{ \Delta Q=\Delta W+\Delta U }

\mathrm{ \triangle U=0 \quad \text { (process } A B C D \text { is cyclic) } }

\mathrm{ \therefore \Delta Q =\Delta W_{A B}+\Delta W_{M C}+\Delta W_{C A} }

\mathrm{ \therefore \Delta W_{C A} =\Delta Q-\Delta W_{A B}-\Delta W_{B C}=5-10-0=-5 \mathrm{~J} . }







 

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Riya

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