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  • An object is placed 40 cm in front of a convex mirror of radius of curvature 20 cm. The image:Option: 1 is real and 8 cm behind the mirror.

An object is placed 40 cm in front of a convex mirror of radius of curvature 20 cm. The image:

Option: 1

is real and 8 cm behind the mirror.


Option: 2

is real and 8 cm in front of the mirror.


Option: 3

is virtual and 8 cm in front of the mirror.


Option: 4

is virtual and 8 cm behind the mirror.


Answers (1)

best_answer

According to new Cartesian sign conventions,
\mathrm{u}=-40 \mathrm{~cm}, \mathrm{R}=+20 \mathrm{~cm}

\mathrm{f}=\frac{\mathrm{R}}{2}=+10 \mathrm{~cm}


According to mirror formula
\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{f}} \therefore \frac{1}{-40}+\frac{1}{\mathrm{v}}=\frac{1}{10}

\frac{1}{\mathrm{v}}=\frac{1}{10}+\frac{1}{40}=\frac{1}{8} \quad \text { or } \mathrm{v}=8 \mathrm{~cm}

Posted by

Kuldeep Maurya

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