Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • An object is placed 40 cm in front of a convex mirror of radius of curvature 20 cm. The image:Option: 1 is real and 8 cm behind the mirror.

An object is placed 40 cm in front of a convex mirror of radius of curvature 20 cm. The image:

Option: 1

is real and 8 cm behind the mirror.


Option: 2

is real and 8 cm in front of the mirror.


Option: 3

is virtual and 8 cm in front of the mirror.


Option: 4

is virtual and 8 cm behind the mirror.


Answers (1)

best_answer

According to new Cartesian sign conventions,
\mathrm{u}=-40 \mathrm{~cm}, \mathrm{R}=+20 \mathrm{~cm}

\mathrm{f}=\frac{\mathrm{R}}{2}=+10 \mathrm{~cm}


According to mirror formula
\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{f}} \therefore \frac{1}{-40}+\frac{1}{\mathrm{v}}=\frac{1}{10}

\frac{1}{\mathrm{v}}=\frac{1}{10}+\frac{1}{40}=\frac{1}{8} \quad \text { or } \mathrm{v}=8 \mathrm{~cm}

Posted by

Kuldeep Maurya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MCC NEET UG 2024 Counselling: Special round schedule out; choice filling begins from November 20
anam-khan

Rajasthan NEET UG counselling board cancels MBBS admissions of 100 students at PMCH
anam-khan

100 MBBS students’ fate uncertain as HC reverses ruling on extra seats at Rajasthan private medical college

Latest Question