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  • An open cubical tank was initially fully filled with water. When the tank was accelerated on a horizontal plane along one of its side it was found that one third of volume of water spilled out. The

An open cubical tank was initially fully filled with water. When the tank was accelerated on a horizontal plane along one of its side it was found that one third of volume of water spilled out. The acceleration was

Option: 1

\mathrm{\mathrm{g} / 3}


Option: 2

\mathrm{\mathrm{2g} / 3}


Option: 3

\mathrm{\mathrm{3g} / 2}


Option: 4

\mathrm{None}


Answers (1)

\mathrm{\begin{aligned} &\begin{aligned} & (a-x) a^2+\frac{1}{2} x a^2=\frac{2}{3} a^3 \\\\ & (a-x)+\frac{x}{2}=\frac{2}{3} a \\\\ & a-\frac{x}{2}=\frac{2}{3} a \end{aligned}\\\\ &a-\frac{x}{2}=\frac{2}{3} a\\\\ &\begin{aligned} & x=\frac{2 a}{3} \\\\ & \therefore \tan \theta=\frac{x}{a}=\frac{a c c .}{g} \quad a=\frac{2}{3} g \end{aligned} \end{aligned}}

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Ramraj Saini

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