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  • Answer please! Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape?

Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape?

  • Option 1)

    1/8

  • Option 2)

    1/4

  • Option 3)

    3/8

  • Option 4)

    1/2

 

Answers (1)

best_answer

As we learnt in

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

 

 Let the number of moles of each gas =x

Fraction of hydrogen escaped =\frac{x}{2}

\frac{ro_{2}}{rH_{2}}=\frac{no_{2}/t}{nH_{2}/t}=\sqrt{\frac{2}{32}}=\frac{1}{4}

=>n_{o}_{2}\frac{1}{4}.nH_{2}=\frac{x}{8}

Hence fraction of oxygen escaped = \frac{1}{8}

 


Option 1)

1/8

This is correct answer

Option 2)

1/4

This is incorrect answer

Option 3)

3/8

This is incorrect answer

Option 4)

1/2

This is incorrect answer

Posted by

prateek

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