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Assertion (A): PPP is crucial for non-photosynthetic tissues, including differentiating tissues, germination of seeds, and tissues that are exposed to darkness.

Reason (R): When Fructose-6-p photosynthesis is not producing NADPH molecules, PPP produces NADPH2 molecules, which are used as reductants in biosynthetic processes.

Option: 1

Both A and R are true and R is the correct explanation of A.


Option: 2

Both A and R are true but R is not the correct explanation of A.


Option: 3

A is true but R is false.


Option: 4

A is false but R is true.

 


Option: 5

Both A and R are false.


Answers (1)

best_answer

PPP is crucial for non-photosynthetic tissues, including differentiating tissues, germination of seeds, and tissues that are exposed to darkness because When Fructose-6-p photosynthesis donot produce NADPH molecules, PPP produces NADPH2 molecules, which are used as reductants in biosynthetic processes.

Option 1 is the correct answer.

 

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