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At very high pressures, the compressibility factor of one mole of a gas is given by :

Option: 1

\frac{pb}{RT}


Option: 2

1 + \frac{pb}{RT}


Option: 3

1 - \frac{pb}{RT}


Option: 4

1 - \frac{b}{\left ( VRT \right )}


Answers (1)

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The vander waals equation for 1 mole of gas is :

                        \left(p+\frac{a}{V^{2}}\right)(V-b)=R T

At very high pressure, the ratio  \frac{a}{V^{2}} can be neglected in comparison to p,

Then equation becomes :

\\ p(V-b)=R T \\ \\ p V=R T+p b \\

Hence, the compressibility factor :

\\\\ Z=\frac{p V}{R T}=1+\frac{p b}{R T}

Posted by

Divya Prakash Singh

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