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Calculate the degree of association for a solution of 0.1 M acetic acid \left ( CH_{3}COOH \right ) with an association constant of 1.75 at 298 K.

Option: 1

0.33


Option: 2

0.50


Option: 3

0.66


Option: 4

0.75


Answers (1)

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The degree of association can be calculated using the formula:
\alpha=1 /(1+\sqrt{(K a / C)})
Where \left(K_a\right) is the association constant and $\mathrm{C}$ is the concentration of the solute. Substituting the values, we get: \alpha=1 /(1+\sqrt{(1.75 / 0.1)})=0.33
Therefore, the degree of association for the given solution is 0.33 .

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HARSH KANKARIA

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