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  • Calculate the enthalpy(in cal) change when 50 mL of 0.02M Ca(OH)2 reacts with 50 ML of 0.02 M HCl. Given the enthalpy of neutralization of strong acid and base is 140 Kcal/mol &nb

Calculate the enthalpy(in cal) change when 50 mL of 0.02M Ca(OH)2 reacts with 50 ML of 0.02 M HCl. Given the enthalpy of neutralization of strong acid and base is 140 Kcal/mol
 

Option: 1

280
 


Option: 2

35


Option: 3

70


Option: 4

140


Answers (1)

best_answer

First calculate the number of moles of HCl,
No. of moles of HCl = MV= (50\times 0.02)/1000 = 10^{-3}
As one mole of  HCl dissociate as  one mole of H+ and one mole of OH-, So moles of H+ ions will also be equal to 10^{-3}

No. of moles of Ca(OH)2 = MV = 50\times0.02 = 10^{-3}
But one mole of Ca(OH)2 gives 1 mole of Ca2+ and 2 moles of OH-, so moles of OH- ions will be equal to 2\times10^{-3}
In the process, only 10^{-3} moles of H+ will be completely neutralised,
Enthalpy Change will be = 140\times 10^{-3}Kcal = 140 cal

Posted by

jitender.kumar

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