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Calculate the reactance in given circuit

Option: 1

\pi


Option: 2

\frac{2}{\pi}


Option: 3

2\pi


Option: 4

\frac{1}{\pi}


Answers (1)

best_answer

As we have learnt,

 

Peack Current -

{i}'_{0}= \frac{v_{0}}{X_{C}}= V_{0}\omega C= V_{0}\left ( 2\pi \nu C \right )

-

 

 

 

 Capacitive resistance is,

X_C = \frac{1}{\omega C}

\omega = 100\pi\;\;\;\;\;C = 10mF

        \\*X_C=\frac{1}{(100\pi)\times10^{-2}} = \frac{1}{\pi}\Omega

 

Posted by

Rishi

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