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Calculate the susceptance (S) in given circuit.

Option: 1

\frac{1}{\pi}


Option: 2

\frac{2}{\pi}


Option: 3

\pi


Option: 4

2\pi


Answers (1)

best_answer

As we have learnt,

 

Capacitive susceptance (S_{C}) -

S_{C}= \frac{1}{X_{c}}= \omega L

\omega L= 2\pi \nu C

-

 

 Susceptance S = \frac{1}{rectance} = \frac{1}{X_C}

\therefore S =\omega C

          \\=(2\pi\times 50)\times 10^{-2} \\=\pi

 

Posted by

Nehul

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