At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is :

  • Option 1)

    \frac{\pi } {2} radian

  • Option 2)

    \pi radian

  • Option 3)

    \frac{\pi } {8} radian

  • Option 4)

    \frac{\pi } {4} radian

 

Answers (1)

 

Intensity of Diffracted light -

I= I_{0}frac{sin^{2} eta }{eta ^{2}}
 

- wherein

Where

eta = frac{pi }{lambda }left ( bsin 	heta 
ight )

 

 At the first minimum, wavelet coming from edge of the slit is balanced out by wavelet coming from middle of the slit hence the phase difference between wavelet from edge of the slit to wavelet from middle of the slit is \pi radian

 


Option 1)

\frac{\pi } {2} radian

This option is incorrect

Option 2)

\pi radian

This option is correct

Option 3)

\frac{\pi } {8} radian

This option is incorrect

Option 4)

\frac{\pi } {4} radian

This option is incorrect

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