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What is the pH of the resulting solution when equal  volumes of 0.1 M NaOH and 0.01 M HCl are mixed?

  • Option 1)

    12.65

  • Option 2)

    2.0

  • Option 3)

    7.0

  • Option 4)

    1.04

 

Answers (1)

best_answer

 

Relation between Ka and Kb -

K_{a}\times K_{b}=K_{W}

or\:P(K_{a})+P(K_{b})=P(K_{W})=14   (at\:298K)

- wherein

K_{a}=dissociation \:constant\:of\:acid

K_{b}=dissociation \:constant\:of\:base

K_{W}=ionic \:product\:of\:water

 

 .01 mole of NaOH will be completely neutralised by .01 mole of HCl. Hence remaining part of NaOH is .09 mole. as equal volume is mixed [OH-]=.04514

P(H) = 14- P(OH) = 14-log [OH-] =12.65

 


Option 1)

12.65

correct

Option 2)

2.0

incorrect

Option 3)

7.0

incorrect

Option 4)

1.04

incorrect

Posted by

prateek

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