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For the reduction of silver ions with copper metal, the standard cell potential was found to be +0.46 V at 25°C. The value of standard Gibbs energy, \Delta G^{\circ} will be (F=96500 C mol-1)

  • Option 1)

    -89.0 kJ

  • Option 2)

    -89.0 J

  • Option 3)

    -44.5 kJ

  • Option 4)

    -98.0 kJ

 

Answers (1)

best_answer

 

Gibbs energy of the reaction -

\Delta_{r}G=-nFE_{cell}

- wherein

\Delta _{r}G = gibbs energy of the reaction

E_{cell}= emf of the cell

nF = amount of charge passed

 

 The cell reaction can be written as

cu+2Ag^{+}\rightarrow cu^{2+}+2Ag

we know that \Delta G^{0}=nFE^{0}_{cell}

\Delta G^{0}=-2\times 96500\times 0.46=-88780J

\Delta G^{0}=-89kJ


Option 1)

-89.0 kJ

This is correct option

Option 2)

-89.0 J

This is incorrect option

Option 3)

-44.5 kJ

This is incorrect option

Option 4)

-98.0 kJ

This is incorrect option

Posted by

prateek

View full answer

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