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  • Can someone help me with this, - Equilibrium - NEET

In a buffer solution containing equal concentration of B^{-} and HB, the k_b \ for \ B^{-} is 10^{-10} . The pH of buffer soluction is:

  • Option 1)

    10

  • Option 2)

    7

  • Option 3)

    6

  • Option 4)

    4

 

Answers (3)

best_answer

As learnt in

Value of Kb -

MOH(aq)\rightleftharpoons M^{+}(aq)+\bar{O}H(aq)

- wherein

K_{b}=\frac{[M^{+}]\:[\bar{O}H]}{[MOH]}


K_{b}=\frac{C\alpha ^{2}}{1-\alpha }

C=initial\:concentration\:of\:base

\alpha =degree\:of\:ionization\:of\:base

 

 P\left ( OH \right ) = PK_b+\log \frac{\left [ B^{-} \right ]}{\left [ HB \right ]}

\because \left [ B^{-} \right ] = \left [ HB \right ]\ \ given

\therefore P\left ( OH \right ) = P\left ( K_b \right )\Rightarrow P\left ( OH \right ) = 10

\therefore P\left ( H \right ) = 14 - P\left ( OH \right ) = 4


Option 1)

10

This option is incorrect

Option 2)

7

This option is incorrect

Option 3)

6

This option is incorrect

Option 4)

4

This option is correct

Posted by

Aadil

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4

 

Posted by

Ankit

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4

Posted by

Ankit

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