If the focal length of objective lens is increased then magnefying power of:

  • Option 1)

    microscope will increase but that of telescope decrease.

  • Option 2)

    microscope and telescope both will increase.

  • Option 3)

    microscope and telescope both will decrease.

  • Option 4)

    microscope will decrease but that of telescope increase.

 

Answers (1)
S subam

 

Compound Microscope -

m= -frac{v_{o}}{u_{o}}cdot frac{D}{u_{e}}
 

- wherein

v_{o}, and , u_{o} is distance from objective.

u_{e} Distance from eyepiece.

Maximum magnification m= -frac{v_{o}}{u_{0}}left ( 1+frac{D}{f_{e}} 
ight )

 

 

Astronomical Telescope -

m= frac{-f_{o}}{f_{e}}left ( 1+frac{f_{e}}{D} 
ight )
 

- wherein

f_{o} = focal length of objective

f_{e}= focal length of eyepiece

 

 For microscope magnifying power \propto \frac{1}{fo}

For telescope magnifying power \propto fo

\therefore magnifying power of microscope decreases and that of telescope increases


Option 1)

microscope will increase but that of telescope decrease.

This option is incorrect 

Option 2)

microscope and telescope both will increase.

This option is incorrect 

Option 3)

microscope and telescope both will decrease.

This option is incorrect 

Option 4)

microscope will decrease but that of telescope increase.

This option is correct 

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