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Consider the following relations for emf of a electrochemical cell:
- emf of cell=(Oxidation potential of anode) - (Reduction potential of cathode)
- emf of cell=(Oxidation potential of anode) + (Reduction potential of cathode)
- emf of cell=(Reduction potential of anode) + (Reduction potential of cathode)
- emf of cell=(Oxidation potential of anode) - (Oxidation potential of cathode)
- Option 1)
2 and 4
- Option 2)
3 and 1
- Option 3)
1 and 2
- Option 4)
3 and 4
Answers (1)
Electro-chemical series -
The standard reduction potential of a large number of electrodes have been measured using standard hydrogen electrode as the reference electrode. These various electrode can be arranged in increasing electrode potential.
-
EMF of a cell = Reduction
potential of cathode- reduction
potential of anode
= Reduction potential of cathode +
oxidation potential of anode
= Oxidation potential of anode -
oxidation potential of cathode.
Option 1)
2 and 4
This is correct option
Option 2)
3 and 1
This is incorrect option
Option 3)
1 and 2
This is incorrect option
Option 4)
3 and 4
This is incorrect option
View full answer
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