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  • Confused! kindly explain, The pressure of H2 required to make the potential of H2 -electrode zero in pure water at 298 K is:

The pressure of H2 required to make the potential of H2 -electrode zero in pure water at 298 K is:

  • Option 1)

    10-14 atm

  • Option 2)

    10-12 atm

  • Option 3)

    10-10 atm

  • Option 4)

    10-4 atm

 

Answers (1)

best_answer

 

Electrode Potential(Nerst Equation) -

M^{n+}(aq)+ne^{-}\rightarrow M(s)

- wherein

E_{(M^{n+}/M)}=E_{(M^{n+}/M)}^{0}-\frac{RT}{nf}ln\frac{[M]}{[M^{n+}]}

[M^{n+}] is concentration of species

F= 96487 C moi^{-1}

R= 8.314 JK^{-1}moi^{-1}

T= Temperature in kelvin

 

 P(H)=7 for water 

-log(H+)=7

(H+)=10-7

2H^{+}(aq)+2e^{-}\rightarrow H_{2}(g)\\ E_{cell}=E_{cell}^{o}-\frac{0.0591}{2}.log\frac{PH_{2}}{\left [ H^{+} \right ]^{2}}

log\left ( \frac{PH_{2}}{10^{-14}} \right )=0\:or PH_{2}=10^{-14}atm

 


Option 1)

10-14 atm

This solution is correct 

Option 2)

10-12 atm

This solution is incorrect 

Option 3)

10-10 atm

This solution is incorrect 

Option 4)

10-4 atm

This solution is incorrect 

Posted by

Aadil

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