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Consider a circular levelled road of radius  10 \mathrm{~m} having coefficient of static friction 0.81 . Three cars (A, B and C) are travelling with speed 7 m/s, 8 m/s and 10 m/s respectively. Which car will skid when it moves in the circular level road? \left(\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2}\right)

Option: 1

Car A


Option: 2

Car B


Option: 3

Car C


Option: 4

None of the above


Answers (1)

best_answer

 From the safe turn condition, the speed of the vehicle (v) must be less than or equal to \sqrt{\mu_s r g}
i.e  \begin{gathered} v \leq \sqrt{\mu_s r g} \\ \end{gathered}

v_{safe}=\sqrt{\mu_s r g}=\sqrt{0.81 \times 10 \times 10}=9 \mathrm{~ms}^{-1}
For Car C,v_{safe}=\sqrt{\mu_s r g} is less than v
The speed of car A, B and C are 7 m/s, 8 m/s and 10 m/s respectively.

The cars A and B will have safe turns. But car C has speed 10 m/s while it turns which exceeds the safe turning speed. Hence, the car 'C' will skid.

Posted by

vishal kumar

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