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Consider a reaction $\mathrm{ A \rightarrow Products}$ -having half -life 50 min- for a certain initial concentration. If the concentration of the reactions becomes doubled, the half-life of the reaction becomes $\mathrm{ 100 \mathrm{~min}}$ .What is order of the reaction :
Option: 1
first order

Option: 2
second order

Option: 3
zero order

Option: 4
third order

Answers (1)

best_answer

$\mathrm{t_{1 / 2}=\frac{[A]_{0}}{2 k}}$

$\mathrm{t_{1 / 2} \propto[A]_{0}}$

Posted by

Ritika Harsh

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