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During an isothermal expansion, a confined ideal gas does - 140 J of work against its surroundings. This implies that:

Option: 1

140 J of heat has been added to the gas


Option: 2

140 J of heat has been removed from the gas


Option: 3

280 J of heat has been added to the gas


Option: 4

No heat is transferred because the process is isothermal


Answers (1)

best_answer

Using

First law in Isothermal Process -

Delta Q= Delta U+Delta W
 

- wherein

Isothermal process

Delta T= 0

Delta U= 0

Heat supplied is equal to work done.

 

 Q = \Delta U+W \ \ \ -(i)

For an isothermal process, \Delta U =0

as  ideal gas does -140 J of work against its surroundings

 \therefore Q= W =-(-140)\ J=140 \ J

Hence, heat is given to the system.

Posted by

Rakesh

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