Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Evaluate the value of given limit: <img alt="\lim _{x \rightarrow \infty} \frac{73 x^3+42 x^2-65}{12 x^3+54 x^2+73}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Clim%20_%7Bx%20%5Crightar

Evaluate the value of given limit: \lim _{x \rightarrow \infty} \frac{73 x^3+42 x^2-65}{12 x^3+54 x^2+73}

Option: 1

\frac{73}{12}


Option: 2

\frac{23}{12}


Option: 3

\frac{53}{12}


Option: 4

\frac{43}{12}


Answers (2)

\lim _{x \rightarrow \infty} \frac{73 x^3+42 x^2-65}{12 x^3+54 x^2+73}

This expression can be written as:

=\lim _{x \rightarrow \infty} \frac{73 x^3\left(1+\frac{42}{73 x}-\frac{65}{73 x^3}\right)}{12 x^3\left(1+\frac{9}{2 x}+\frac{73}{12 x^3}\right)}

=\lim _{x \rightarrow \infty} \frac{73\left(1+\frac{42}{73 x}-\frac{65}{73 x^3}\right)}{12\left(1+\frac{9}{2 x}+\frac{73}{12 x^3}\right)}

Putting value of limit:

\begin{aligned} & =\frac{73(1)}{12(1)} \\ & =\frac{73}{12} \end{aligned}

Posted by

Ramraj Saini

View full answer

73/12

Posted by

Guru G

View full answer

Similar Questions

Latest Question