Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Find out the magnitude of work (in kJ) done by one mole of an ideal gas for expansion. <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAOYAAADHCAYAAAANmi8oAAAgAElEQVR4nO2de3RU1fXH

Find out the magnitude of work (in kJ) done by one mole of an ideal gas for expansion.

Option: 1

-1


Option: 2

2


Option: 3

6


Option: 4

60


Answers (1)

best_answer

Work is a path function and not state function and area under \mathrm{P-V} curve gives work.

So, work will be the total area of the Trapezium

\therefore \mathrm{|work| = \frac{1}{2} \times \textrm{(sum of parallel sides)} \times \textrm{(distance between the parallel sides)}}

\therefore \mathrm{|work| = \frac{1}{2} \times 6 \times 20=60 \times 10^{-5} \ bar-lit}

\therefore \mathrm{|work| = 60 \times 10^{5} \ bar-lit=60 \times 10^{5} \times 10^{-3} bar-m^3=6000 J}

Thus, the magnitude of work done is 6 kJ

 

Posted by

Kuldeep Maurya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'NEET 2025 in dark': MP High Court orders re-test for Indore, Ujjain students; MCC counselling delayed
anam-khan

Punjab’s new 2-year MBBS bond, fee hike ‘exploitation’, ‘unfair’; interns, doctors shut OPDs in protest
anam-khan

NEET UG 2025 counselling likely to begin on July 1; AIQ seat allocation, court hearing updates

Latest Question