Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Find the surface energy (in Joule) of water kept in a cylindrical vessel of radius 6cm. surface tension of water =<img alt="75\times 10^{-3}Nm^{-1}" src="/latex-image/?75%5Ctimes%2010%5E%7B-3%7DNm%

Find the surface energy (in Joule) of water kept in a cylindrical vessel of radius 6cm. surface tension of water =75\times 10^{-3}Nm^{-1}

Option: 1 0.0017

Option: 2 0.00085

Option: 3 0.00042

Option: 4 0.085

Answers (1)

best_answer

As we learned 

 

Definition of Surface Tension -

W=T\Delta A

If \ \Delta A=1,then\ T=W

- wherein

T\rightarrow Surface \: tension

W\rightarrow work \: done

 

 Surface \: energy=TA

=\frac{22}{7}\times (6\times 10^{-2})^{2}\times 75\times 10^{-3}J

=8.5\times 10^{-4}J

 

Posted by

Anam Khan

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'NEET 2025 in dark': MP High Court orders re-test for Indore, Ujjain students; MCC counselling delayed
anam-khan

Punjab’s new 2-year MBBS bond, fee hike ‘exploitation’, ‘unfair’; interns, doctors shut OPDs in protest
anam-khan

NEET UG 2025 counselling likely to begin on July 1; AIQ seat allocation, court hearing updates

Latest Question