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  • For a rxn <img alt="\mathrm{2 A B_2(g)\rightleftharpoons A_2 B_2(g)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2%20A%20B_2%28g%29%5Crightleftharpoons%20A_2%20B_2%28g%29%7D"

For a rxn \mathrm{2 A B_2(g)\rightleftharpoons A_2 B_2(g)} when \mathrm{\Delta S=-163.0 \, \mathrm{JK}^{-1}} and  \mathrm{\Delta H=-69.48 \, \mathrm{kJ} \, \mathrm{mol}^{-1}} What will be the magnitude of \mathrm{\Delta G} at 298 \mathrm{~K}

Option: 1

\mathrm{20.906 \mathrm{~kJ} / \mathrm{mol}}


Option: 2

\mathrm{35.62 \mathrm{~kJ} / \mathrm{mol}}


Option: 3

\mathrm{28.95 \mathrm{~kJ} / \mathrm{mol}}


Option: 4

\mathrm{40.692 \mathrm{~kJ} / \mathrm{mol}}


Answers (1)

best_answer

\mathrm{\begin{aligned} \Delta H & =-69.48\, \mathrm{kJmol}^{-1} \\\\ \Delta S & =-163.0\, \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \\\\ T & =298 \mathrm{~K} \end{aligned}}

By Gib's free Energy 

\mathrm{\begin{aligned} & \Delta G=+69.48 \mathrm{~kJ} / \mathrm{mol}-\left(298 \times \frac{-163}{1000} \mathrm{~kJ}\right) \\ & \Delta G=-20.906 \quad 1 \mathrm{~kJ}=1000 \mathrm{~J} . \\\\ & |\Delta G|=20.906 \mathrm{~kJ} / \mathrm{mol} \end{aligned}}

Posted by

SANGALDEEP SINGH

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