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  •  for NaCl, HCl,and NaAc are 126.4,425.9 and 91 S cm2 mol

\Lambda_{m}^{\circ} for NaCl, HCl,and NaAc are 126.4,425.9 and 91 S cm2 mol-1, respectively. Calculate \Lambda^{\circ} for HAc.

Option: 1

390.5


Option: 2

643.3


Option: 3

91


Option: 4

-390.5


Answers (1)

best_answer

\begin{aligned} \Lambda_{\mathrm{m}(\mathrm{HA} \mathrm{c})}^{\circ} &=\Lambda_{\mathrm{m}(\mathrm{HCl})}^{\circ}+\Lambda_{\mathrm{m}(\mathrm{NaAc})}^{\circ}-\Lambda_{\mathrm{m(NaCl)}}^{\circ} \\ &=(425.9+91.0-126.4) \mathrm{\: S\: cm}^{2} \mathrm{\: mol}^{-1} \\ &=390.5 \mathrm{\: S\: cm}^{2} \mathrm{\: mol}^{-1} \end{aligned}

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Ritika Jonwal

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