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  • For the irreversible expansion of an ideal gas under isothermal conditions, the correct option is :    Option: 1 <img alt=

For the irreversible expansion of an ideal gas under isothermal conditions, the correct option is :
 

 

Option: 1

\Delta U=0,\Delta S_{total}=0


Option: 2

\Delta U\neq 0,\Delta S_{total}\neq 0


Option: 3

\Delta U= 0,\Delta S_{total}\neq 0

 


Option: 4

\Delta U\neq 0,\Delta S_{total}= 0


Answers (1)

best_answer

For irreversible expansion of an ideal gas under isothermal condition -

We know, for a spontaneous process, \Delta \mathrm{S}_{\text {total }}>0 and since the irreversible process is always spontaneous therefore \Delta \mathrm{S}_{\text {total }}>0.

And \Delta \mathrm{T}=0 for isothermal process.

Now, \Delta \mathrm{U}=\mathrm{n} \mathrm{C}_{\mathrm{V}} \Delta \mathrm{T}

So, \Delta \mathrm{U}=0

Correct option  \mathrm{\Delta U=0, \Delta S_{\text {total }} \neq 0}.

Therefore, the correct option is (3).

Posted by

Divya Prakash Singh

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