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  • For the reaction A + B products, it is observed that:

For the reaction A + B \longrightarrow products, it is observed that:

  1. on doubling the initial concentration of A only, the rate of reaction is also doubled and
  2. on doubling the initial concentration of both A and B, there is a change by a factor of 8 in the rate of the reaction.

The rate of this reaction is given by:

Option: 1

rate =k [A] [B]^2


Option: 2

rate =k [A]^2 [B]^2


Option: 3

rate = k [A] [B]


Option: 4

rate = k [A]^2 [B]


Answers (1)

best_answer

For the reaction, 

A+B \rightarrow Product

Let initially rate law is,

Rate = k[A]x[B]y

On doubling the initial concentration of A, the rate of reaction is also doubled, therefore, 

                \\ \text{Rate}\propto [A]^{1} \\ \\ \text{Rate}=k[A]^{1}[B]^{y} .........(1)

If the concentration of A and B both are doubled, the rate gets changed by a factor of 8.

\\ \text{8 x Rate}=k [2A]^{1}[2B]^{y}..............(2)

Dividing eq (2) by eq. (1),

8 = 21 x 2y

2y = 4

y = 2

Now, Rate = k[A]1[B]2

Order of the reaction is = 1+2 = 3

The Correct answer is option 1.

Posted by

shivangi.bhatnagar

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