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  • From a disc of radius R and mass   9M , concentrically remove a small disc of mass M and radius

From a disc of radius R and mass   9M , concentrically remove a small disc of mass M and radius \frac{R}{3}. The moment of inertia of the disk remaining around an axis perpendicular to the plane of the disk and passing through its center is:

Option: 1

\frac{40}{9}MR^2


Option: 2

MR^2


Option: 3

4MR^2


Option: 4

\frac{4}{9}MR^2


Answers (1)

best_answer

Answer:      \frac{40}{9}MR^2

Explanation:

The moment of inertia of the disk about the axis perpendicular to the plane of the disk and passing through the center is:

                            I=I_1-I_2

= \frac{9\ MR^2}{2}-\frac{MR^2}{18}

 = \frac{81MR^2-\ MR^2}{18}

 = \frac{40}{9}MR^2

Posted by

SANGALDEEP SINGH

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