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Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3, Given that \Lambda _{Al^{3+}}^{\circ} and \Lambda^{\circ}_{SO_{4}^{2-}} are the equivalent conductances at infinite dilution of the respective ions?

  • Option 1)

    \frac{1}{3}\Lambda ^{\circ}_{Al^{3+}}+\frac{1}{2}\Lambda ^{\circ}_{SO_{4}^{2-}}

  • Option 2)

    2\Lambda ^{\circ}_{Al^{3+}}+3\Lambda ^{\circ}_{SO_{4}^{2-}}

  • Option 3)

    \Lambda ^{\circ}_{Al^{3+}}+\Lambda ^{\circ}_{SO_{4}^{2-}}

  • Option 4)

    (\Lambda ^{\circ}_{Al^{3+}}+\Lambda ^{\circ}_{SO_{4}^{2-}})\times6

 

Answers (1)

best_answer

 

Application of Kohlrausch's law -

Calculation of molar conductivities of weak electrolyte at infinite dilution.

-

 

 At infinite dilution, when dissociation is complete, each ion makes a definite contribution towards molar conductance of the electrolyte irrespective of nature of other ion with which it is associated.


Option 1)

\frac{1}{3}\Lambda ^{\circ}_{Al^{3+}}+\frac{1}{2}\Lambda ^{\circ}_{SO_{4}^{2-}}

incorrect

Option 2)

2\Lambda ^{\circ}_{Al^{3+}}+3\Lambda ^{\circ}_{SO_{4}^{2-}}

incorrect

Option 3)

\Lambda ^{\circ}_{Al^{3+}}+\Lambda ^{\circ}_{SO_{4}^{2-}}

correct

Option 4)

(\Lambda ^{\circ}_{Al^{3+}}+\Lambda ^{\circ}_{SO_{4}^{2-}})\times6

incorrect

Posted by

prateek

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