Which of the following statements is correct for a reversible process in a state of equilibrium?

  • Option 1)

    \Delta G=2.30\ RT\ log \ K

  • Option 2)

    \Delta G^{o}=-2.30\ RT\ log \ K

  • Option 3)

    \Delta G^{o}=2.30\ RT\ log \ K

  • Option 4)

    \Delta G=-2.30\ RT\ log \ K

 

Answers (1)

As we discussed in concept

Relation between Gibbs energy and reaction Quotient -

\bigtriangleup G=\bigtriangleup G^{\circ}+RTl_{n}Q

 

 

- wherein

\bigtriangleup G^{\circ} is standard Gibbs energy.

Q\rightarrow Reaction\:Quotient

 

 \Delta G^{\circ}= -2.30\:RT\:log\:K

 


Option 1)

\Delta G=2.30\ RT\ log \ K

This option is incorrect.

Option 2)

\Delta G^{o}=-2.30\ RT\ log \ K

This option is correct.

Option 3)

\Delta G^{o}=2.30\ RT\ log \ K

This option is incorrect.

Option 4)

\Delta G=-2.30\ RT\ log \ K

This option is incorrect.

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