Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Help me understand! Three blocks A, B and C, of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is:

Three blocks A, B and C, of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is:

  • Option 1)

    6 N

  • Option 2)

    8 N

  • Option 3)

    18 N

  • Option 4)

    2 N

 

Answers (1)

best_answer

As we learnt in 

When 3 Blocks are in Contact -

 

- wherein

Use:F_{net}=ma

a=frac{F}{m_{1}+m_{2}+m_{3}}


f_{1}=frac{(m_{2}+m_{3})F}{m_{1}+m_{2}+m_{3}}

f_{2}=frac{m_{3}F}{m_{1}+m_{2}+m_{3}}

 

 F = m a

a = F/m = 14 |(4+2+1) = 2m| 1s2 

F = ma

F = (2+1) 2

F =3 \times 2 = 6 N

Contact force between A & B is used to move the bodies B & C only.


Option 1)

6 N

Correct

Option 2)

8 N

Incorrect

Option 3)

18 N

Incorrect

Option 4)

2 N

Incorrect

Posted by

prateek

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NTA Overhaul: 1,000 secure exam centres, biometrics to prevent fraud, question paper changes, suggests panel
anam-khan

NEET syllabus 2025 out; NMC uploads subject-wise topics
anam-khan

What changes in NEET UG? Experts’ panel suggests multi-stage exam, security overhaul, simpler process to NTA

Latest Question