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  • How to solve this problem- - Hydrocarbons - NEET

In the reaction 

 H-C\equiv CH \frac{(1)N_{a}NH_{2}/liq.NH_{3}}{(2)CH_{3}CH_{2}Br}X\\ \frac{\left ( 2 \right )N_{a}NH_{2}/liq.NH_{3}}{\left ( 2 \right )CH_{3}CH_{2}Br}Y 

X and Y are

  • Option 1)

    X=1-Butyne; Y=3-Hexyne

  • Option 2)

    X=2-Butyne; Y=3-Hexyne

  • Option 3)

    X=2-Butyne; Y=3-Hexyne

  • Option 4)

    X=1-Butyne; Y=2-Hexyne

 

Answers (1)

As we learnt in 

Birch Reduction -

Alkynes on reduction with sodium in liquid NH3 form trans alkene.

- wherein

 

X=1-Butyne,      Y= 3-Hexyne


Option 1)

X=1-Butyne; Y=3-Hexyne

This option is correct

Option 2)

X=2-Butyne; Y=3-Hexyne

This option is incorrect

Option 3)

X=2-Butyne; Y=3-Hexyne

This option is incorrect

Option 4)

X=1-Butyne; Y=2-Hexyne

This option is incorrect

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