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A thin prism of angle 15^{\circ} made of glass of refractive index \mu _{1} = 1.5 is combined with another prism of glass of refractive index \mu _{2} = 1.75. The combination of the prism produces dispersion without deviation. The angle of the second prism should be

  • Option 1)

    7^{\circ}

  • Option 2)

    10^{\circ}

  • Option 3)

    12^{\circ}

  • Option 4)

    5^{\circ}

 

Answers (1)

best_answer

As we learnt in

Deviation from thin prism -

delta = left ( mu -1 ight )A

- wherein

Applicable when A is very small

 ( i.e. thin prism )

 

 Net deviation = 0 

 \therefore \delta_{1}+\delta_{2}=0

\Rightarrow (\mu_{1}-1)A_{1}=(\mu_{2}-1)A_{2}

\Rightarrow |A_{2}|=\frac{\mu_{1}-1}{\mu_{2}-1}A_{1}=\frac{1.5-1}{1.75-1}\times 15^{o}=\frac{0.5}{0.75}\times 15^{o}

A_{2}=10^{o}

 


Option 1)

7^{\circ}

Incorrect

Option 2)

10^{\circ}

Correct

Option 3)

12^{\circ}

Incorrect

Option 4)

5^{\circ}

Incorrect

Posted by

prateek

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