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If  the equilibrium constant for N2(g) + O2(g) \rightleftharpoons 2NO(g) is K, the equilibrium constant for \frac{1} {2}\text{N}_2 \left( \text{g} \right) + \frac{1} {2}\text{O}_2 \left( \text{g} \right) \rightleftharpoons \text{NO}\left( \text{g} \right) will be:

  • Option 1)

    K1/2

     

  • Option 2)

    \frac{1}{2}K

  • Option 3)

    K

     

  • Option 4)

    K2

 

Answers (1)

best_answer

As we learned in concept

Equilibrium constant for the reverse reaction -

Equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the reaction in the forward direction.

- wherein

K'_{c}=\frac{1}{K_{c}}

{K'_{c}}   is  equilibrium constant for reverse direction.

 

 N_{2}+O_{2}\rightleftharpoons 2NO, K

\frac{1}{2}N_{2}+\frac{1}{2}O_{2}\rightleftharpoons No, K^{1}=\sqrt{K} 


Option 1)

K1/2

 

Option is correct

Option 2)

\frac{1}{2}K

Option is incorrect

Option 3)

K

 

Option is incorrect

Option 4)

K2

Option is incorrect

Posted by

Aadil

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