if a stone is released from a 30 m high tower and at same time a stone with 25 m/s thrown vertically upward from the base of that tower then find the position at which both stones will meet and time taken by them to meet
Answers (1)
@deeksha
Relative distance=30 m
Relative speed= 25 m/s
Relative acceleration=0
SO use
so
Now for particle released from a 30 m high tower
a=-g m/s2
and u=0
t=1.2
so use
both stones will meet will meet 7.2 m below from the top of tower