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If n = 6 the correct sequence for filling of electrons will be :

Option: 1

n s \rightarrow n p\rightarrow (n-1) d \rightarrow(n-2) f


Option: 2

n s \rightarrow(n-2) f \rightarrow(n-1) d \rightarrow n p


Option: 3

n s \rightarrow(n-1) d \rightarrow(n-2) f \rightarrow n p


Option: 4

n s \rightarrow(n-2) f \rightarrow n p \rightarrow(n-1) d


Answers (1)

best_answer

According to Aufbau Principle, the electrons in an atom are filled in the increasing order of their energies. 
The order of orbital energies is determined by (n+l) rule. 
If (n+l) value is the same for two orbitals, then the orbital with the lower value of n is filled first.
For n = 6
6s = 6+0 = 6
6p = 6+1 = 7
5d = 5+2 = 7
4f = 4+3 = 7

So, increasing the order of energy will be

6s < 4f < 5d < 6p

Therefore, the correct option is (2).

Posted by

Pankaj

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