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If percentage error in measurement of resistance R is 5% and that of in a measurement of current I is 2%, then the maximum percentage error in voltage V will be :
Option: 1
3

Option: 2
2.5

Option: 3
7

Option: 4
5

Answers (1)

V= IR

$\frac{\Delta V}{V} = \frac{\Delta I}{I} + \frac{\Delta R}{R}\Rightarrow\frac{\Delta V}{V}\times100 = \frac{\Delta I}{I}\times100 + \frac{\Delta R}{R}\times100=5 \%+ 2 \%=7 \%$

Posted by

Ramraj Saini

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