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  •  In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference patternOption:

 In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference pattern

Option: 1

the intensities of both the maxima and the minima increase.


Option: 2

the intensity of the maxima increases and the minima has zero intensity.


Option: 3

 the intensity of the maxima decreases and that of the minima increases.


Option: 4

 the intensity of the maxima decreases and the minima has zero intensity.

 


Answers (1)

best_answer

In the interference pattern of Young's double slit experiment maximum and minimum intensity is given as

\mathrm{I_{\max }=\left(\sqrt{I_{1}}+\sqrt{ } I_{2}\right)^{2}}
\mathrm{I_{\min }=\left(\sqrt{I_{1}}-\sqrt{I_{2}}\right)^{2}}

Here \mathrm{I_{1}} has been doubled and \mathrm{I_{2}} remains same. Therefore both \mathrm{I_{1}} and \mathrm{I_{2}} will increase.

Hence (A) is correct

Posted by

Divya Prakash Singh

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