In a double slit experiment , when light of wavelength 400 nm was used , the angular width of the first minima formed on a screen palced 1 m away , was found to be 0.2 \degree . what will be the angular  width of the first minima , if the entire experimental apparatus is immersed in water ? 

 

 

0.15 \degree

 

 

0.05 \degree

 

0.1 \degree

 

Answers (1)

 

Refractive index -

mu = frac{c}{v}
 

- wherein

c= speed of light in vacuum.

v= speed of light in medium.

 

 

Young Double Slit Experiment -

- wherein

y=Delta xcdot left ( frac{D}{d} 
ight )

y= Distance of a point on screen from central maxima

Delta x= Path difference at that point

 

Fringe Width in a medium -

{\beta }'= \frac{\beta }{\mu }

- wherein

Since wavelength in a medium become \lambda = \frac{\lambda _{o}}{\mu }

 

 

 

Angular width =\theta \ \alpha \ \ \lambda

and \mu =\frac{c}{v}=\frac{\lambda _1}{\lambda _2}=\frac{\theta _1}{\theta _2}

  \theta _2=\frac{\theta _1 }{\mu }\Rightarrow \frac{0.2*3}{4}=0.15^0

 

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