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  • In a hydraulic lift at a service station, the radii of large and small pistons are in the ratio 20 : 1 what weight placed on the small piston will be sufficient to lift a car of mass 1200Kg<div

In a hydraulic lift at a service station, the radii of large and small pistons are in the ratio 20 : 1 what weight placed on the small piston will be sufficient to lift a car of mass 1200Kg

Option: 1

3 Kg


Option: 2

30 Kg


Option: 3

300 Kg


Option: 4

None of the above 


Answers (1)

best_answer

As we have learnt

Condition of Hydraulic Lift -

A> > a\: \: therefore

F> > f

- wherein

So heavy load placed on the larger Piston is easily lifted upward 

 

 From Pascals law

\frac{F_{1}}{F_{2}}=\frac{A_{1}}{A_{2}}=\frac{F_{1}}{1200*10}=\frac{\pi r_{1}^2}{\pi r_{2}^2}\Rightarrow F_{1}=12000*\frac{\pi r_{1}^2}{\pi r_{2}^2}\Rightarrow 12000*\frac{1}{400}=30N=3kg

 

Posted by

Gunjita

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