Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

In a liquid, a force of 5N, a velocity gradient of du/dx, and a contact area of 20m2 are needed to sustain the flow of layers. What then is the significance of viscosity?
Option: 1
$\quad 6.25 \mathrm{dz} / \mathrm{du}$

Option: 2
$\quad 0.15 \mathrm{dz} / \mathrm{du}$

Option: 3
$\quad 0.25 \mathrm{dz} / \mathrm{du}$

Option: 4
$\quad 0.2 \mathrm{dz} / \mathrm{du}$

Answers (1)

best_answer

$F=\left(\eta \times A \times \frac{d u}{d x}\right)$

where,

F = force required to maintain the flow

$\eta$ = viscosity

A = area of contact

$\frac{du}{dx}=velocity\, gradient$

$We\, \, have,$

$\text { F }=5 \mathrm{~N}$

$A=20 \mathrm{~m}^2$

$\frac{d u}{d x}=\frac{d u}{d x}$

There fore, we can rewrite the formula as:

$\eta=F /\left(A \times \frac{d u}{d x}\right)$

Substituting the given values, we get:

$\eta=5 \mathrm{~N} /\left(20 m^2 d u / d x\right) \\ \eta=0.25 \mathrm{du} / \mathrm{dx}$

The formula for the force necessary to keep layers flowing is $\mathrm{F}=\frac{\mathrm{Adu}}{\mathrm{dz}}$

, where is the coefficient of viscosity, A is the area of contact and $\frac{\mathrm{du}}{\mathrm{dz}}$

is the velocity gradient. Thus, by replacing, we have $0.25 \frac{\mathrm{du}}{\mathrm{dz}}$

The following formula determines the force necessary to keep liquid layers flowing:

Posted by

chirag

View full answer

NEET 2024 Most scoring concepts

Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2025: NTA's 5 new rules, changes for medical entrance exam

anam-khan

NEET UG 2025: New tie-breaking rule, independent expert panel to resolve through ‘random process’

anam-khan

NEET Registration 2025 Live: NTA NEET UG application form out at neet.nta.nic.in; exam schedule

Latest Question