In a monohybrid cross between two pea plants, one with a homozygous dominant genotype (AA) and the other with a heterozygous genotype (Aa), what is the expected genotypic ratio of the offspring?
1:2:1
1:1
3:1
1:0:1
In a monohybrid cross, where only one trait is considered, the expected genotypic ratio can be determined using a punnett square. In this case, the homozygous dominant parent (AA) can only contribute the dominant allele (A), and the heterozygous parent (Aa) can contribute either the dominant allele(A) or recessive allele(a). Therefore, the possible genotypes in the offspring are AA, Aa and aa. By analyzing the punnett square, we find that the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive, which corresponds to option (a).
A |
A |
|
A |
AA |
AA |
a |
Aa |
Aa |