In a monohybrid cross, work out the distribution of phenotypic features in the F1 generation after a cross between a heterozygous male and a homozygous female using a Punnett square.
50% each homozygous and heterozygous
In F1 generation, only dominant trait will be exhibited
In F1 generation, only recessive trait will be exhibited
75% homozygous and 25% heterozygous
In a monohybrid cross, a female individual is represented as tt (homozygous dwarf) and a male is represented as Tt (heterozygous tall), the required Punnett square to illustrate their cross is given as follows:
CROSS: Heterozygous tall (male) X Homozygous dwarf (female)
Parent genotype: Tt [Crossing] tt
P. gametes: T, t t, t
F1 generation: Tt, Tt, tt, tt
(Punette square)
T | t | |
t | Tt | tt |
t | Tt | tt |
Genotype: Tt: tt= 2:2 =1:1
Phenotype: Tall (Tt): Dwarf (tt) =1:1
Thus, in the F1 generation, all progenies will be phenotypically dominant, i.e. tall, whereas genotypically 50% will be homozygous tall and 50% will be heterozygous tall.
Thus, the correct answer is option 1).