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In a monohybrid cross, work out the distribution of phenotypic features in the F1 generation after a cross between a heterozygous male and a homozygous female using a Punnett square.
 

Option: 1

50% each homozygous and heterozygous 
 


Option: 2

In F1 generation, only dominant trait will be exhibited 
 


Option: 3

In F1 generation, only recessive trait will be exhibited 
 


Option: 4

75% homozygous and 25% heterozygous 
 


Answers (1)

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In a monohybrid cross, a female individual is represented as tt (homozygous dwarf) and a male is represented as Tt (heterozygous tall), the required Punnett square to illustrate their cross is given as follows: 

CROSS: Heterozygous tall (male) X Homozygous dwarf (female)

Parent genotype:            Tt         [Crossing]          tt

P. gametes:     T, t                      t, t

F1 generation: Tt, Tt, tt, tt
(Punette square)

  T t
t Tt tt
t Tt tt

Genotype: Tt: tt= 2:2 =1:1
Phenotype: Tall (Tt): Dwarf (tt) =1:1

Thus, in the F1 generation, all progenies will be phenotypically dominant, i.e. tall, whereas genotypically 50% will be homozygous tall and 50% will be heterozygous tall.

Thus, the correct answer is option 1).

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Rishi

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