In a population of birds, the frequency of the dominant allele for feather color is 0.6. What is the population's expected frequency of heterozygous individuals, assuming Hardy-Weinberg equilibrium?
0.12
0.36
0.48
0.72
Applying the Hardy-Weinberg Equation,
The frequency of the dominant allele is p = 0.6
The frequency of the recessive allele is q = 1 - p = 0.4.
The frequency of heterozygous individuals is 2pq, where p and q represent the frequencies of the dominant and recessive alleles, respectively.
Therefore, the expected frequency of heterozygous individuals in the population is 2 x 0.6 x 0.4 x 1000 = 480/1000 = 0.48.
Option 3 is the correct answer