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In a zener-regulated power supply a zener diode with $v_2=6.0 \mathrm{~V}$ is used for regulation. The load current is to be $4 \mathrm{~mA}$ and the unregulated input is $10 \mathrm{~V}$ . What should be the value of series resistance R ?
Option: 1
$140 \Omega$

Option: 2
$150 \Omega$

Option: 3
$162 \Omega$

Option: 4
$167 \Omega$

Answers (1)

best_answer

Given $I_L=4.0 \mathrm{~mA}$
Let us take $I_z$ to be fivetimes $I_L$ or $I_z=20 \mathrm{~mA}$ .

Total current $I=I_z+I_L=24 \mathrm{~mA}$ .
Input voltage $V_{m}=10 \mathrm{~V}$
zener diode voltage $V_z=6 \mathrm{~V}$
Voltage drop across resistance
$\begin{aligned} \Rightarrow & V_R=V_{\text {in }}-V_2=(10-6) \mathrm{V}=4 \mathrm{~V} \\ \Rightarrow & \frac{V_R}{I_R}=\frac{.4}{24 \times 10^{-3}} \Omega=167 \Omega \end{aligned}$

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Rishi

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