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In an irreversible process in which only Pressure-Volume is taking place at constant T and P the change in Gibbs free energy (dG) and change in entropy (dS) are related as :

Option: 1

(dS))_{V,E}> 0,(dG)_{T,P}> 0
 


Option: 2

(dS))_{V,E}> 0,(dG)_{T,P}< 0


Option: 3

(dS))_{V,E}< 0,(dG)_{T,P}< 0

 


Option: 4

(dS))_{V,E}= 0,(dG)_{T,P}= 0


Answers (1)

best_answer

An irreversible process is a process that is spontaneous, so for spontaneity change in entropy (dS) must be positive and the change in Gibbs free energy (dG) should be negative.
Hence, option number (2) is correct.

Posted by

sudhir kumar

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