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  • In Carius method for detection of percentage of Phosphorus, % <img alt

In Carius method for detection of percentage of Phosphorus,

%P= \frac{62*W_1*100}{222*W_2}

W_1,W_2 respectively are

Option: 1

Weight of BaSO_4 and weight of organic compound


Option: 2

Weight of H_2O and weight of organic compound


Option: 3

Weight of organic compound and weight of Mg_2P_2O_7


Option: 4

Weight of Mg_2P_2O_7 and weight of organic compound


Answers (1)

best_answer

As we learnt

 

Quantitative analysis of Phosphorus -

 

percentage\:of\:Phosphorus=\frac{62\times m_{1}\times 100}{222\times m}
 


m_{1}=weight\:of\:Phosphorus=Mg_{2}P_{2}O_{7}


m= weight of Organic Compunds

- wherein

 

 

 

Posted by

Kuldeep Maurya

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