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In the shown arrangement of the experiment of a meter bridge, if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

Option: 1

x


Option: 2

\frac{x}{4}


Option: 3

4x


Option: 4

2x


Answers (1)

best_answer

At null point, \mathrm{\frac{R_1}{R_2}=\frac{R_3}{R_4}=\frac{x }{(100-x)}}. If radius of the wire is doubled, then the resistance of A C will change and the resistance of C B will also change. But since \mathrm{\frac{R_1}{R_2}} does not change, so \mathrm{\frac{R_3}{R_4}} should also not change at null point. Therefore, point C does not change

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