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  • In this equation: <img alt="\mathrm{2KClO}_{3} \rightarrow \mathrm{2KCl}+\mathrm{3O}_{2}" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2KClO%7D_%7B3%7D%20%5Crighta

In this equation:

\mathrm{2KClO}_{3} \rightarrow \mathrm{2KCl}+\mathrm{3O}_{2}
What will be the mass (in g) of O2 produced from 1.23g of KClO3?

 

Option: 1

0.482


Option: 2

0.545


Option: 3

0.758


Option: 4

0.345


Answers (1)

best_answer

According to the equation,

2 moles of KClO3 will produce 3 moles of O2.

Thus moles of KClO3 = 1.23 / 123
                                = 0.01 moles

Therefore, 0.01 moles of KClO3 will produce = (3 x 0.01) / 2
                                                                 = 0.015 moles

thus mass of O2 = 0.015 x 32
                         = 0.48g

Therefore, Option(1) is correct

Posted by

shivangi.bhatnagar

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