In Young's double-slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent courses is doubled, the fringe width becomes
Option: 1 double
Option: 2 half
Option: 3 four times
Option: 4 one-fourth
The fringe width,
Where, the wavelength of light
d=distance of slit
D=distance of the screen from the slit.
According to the question,
So, the fringe width will be quadrupled.